If the constraint is defined as 3D + 2W ≤ 18, what is the maximum value of D?

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Prepare for UCF's QMB3602 Business Research for Decision Making Exam 2. Utilize interactive flashcards and multiple choice questions, complete with detailed explanations. Enhance your exam readiness now!

To find the maximum value of ( D ) in the constraint ( 3D + 2W \leq 18 ), we can first isolate ( D ). Rearranging the equation gives us:

[ 3D \leq 18 - 2W ]

Now, dividing every term by 3 yields:

[ D \leq 6 - \frac{2}{3}W ]

From this inequality, it is clear that ( D ) is dependent on the value of ( W ). To maximize ( D ), we must minimize the term ( -\frac{2}{3}W ). The smallest possible value of ( W ) is 0 (assuming ( W ) cannot be negative), leading us to:

[ D \leq 6 - 0 \implies D \leq 6 ]

Therefore, the maximum possible value for ( D ) is 6. This means if ( W = 0 ), then ( D ) reaches its maximum value of 6 while still satisfying the constraint ( 3D + 2W \leq 18 ).

Consequently, among the options provided,